x=6,x^2-4x+3

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Solution for x=6,x^2-4x+3 equation: 



x=6.x^2-4x+3

We move all terms to the left:

x-(6.x^2-4x+3)=0

We get rid of parentheses

-6.x^2+x+4x-3=0

We add all the numbers together, and all the variables

-6x^2+5x-3=0

a = -6; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·(-6)·(-3)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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